Stoichiometry
Problems #1
Use the following equation to answer the questions below:
Mg3N2(s)
+ 3 H2O(l)
® 3 MgO(s) + 2 NH3(g)
a) How many moles of
NH3 are formed from 1.80 moles of H2O?
b) How many grams of Mg3N2
are needed to form 0.892 moles of NH3?
c) How many grams of H2O
are needed to form 3.40 grams of NH3?
d) How many molecules
of NH3are formed when 0.90 moles of H2O are used up?
Answers to Stoichiometry
Problems #1
a) 1.80 mol H2O x 2 mol NH3 = 1.20 mol NH3
b) 0.892 mol NH3 x 1
mol Mg3N2
x 100.9 g Mg3N2 = 45.0 g Mg3N2
2
mol NH3 1
mole Mg3N2
c) 3.40 g NH3 x 1
mole NH3 x 3 mol H2O x 18.0
g H2O = 5.40 g H2O
17.0 g NH3 2 mol NH3 1
mol H2O
d) 0.90 mol H2O x 2
mol NH3 x 6.02 x 1023 molecules NH3
3 mol H2O 1 mol NH3
= 3.6 x 1023 molecules NH3
= 3.6 x 1023 molecules NH3
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